How to find the best Pandora Black Friday and Cyber Monday deals

Published: Tuesday 08 November, 2016
Black Friday and Cyber Monday, the biggest shopping event of year, is almost upon us with retailers across Britain poised to heavily discount big ticket items and kick-start the gift-buying season on November 25.

Although traditionally the day focuses on gadget and tech discounts, lots of retailers now want a slice of the Black Friday pie meaning you can scoop up bargains on almost anything.

International Danish jeweller Pandora has for several years offered discounts in the UK, and a special edition Black Friday charm bracelet for its North American and Canadian customers. But what will be on offer in the UK this year?

What deals can we expect?

It's still a little too early to tell as retailers tend to be very secretive about what they're planning to discount, but it's likely there will be some savings to be made at Pandora.

As far as we know its Black Friday offerings will be available online from Friday, November 25 at 00:01, to Sunday, November 27 at 11:59pm.

In fact, they're already offering a free Christmas present ornament if you spend £125 or more. The retailer, which is known for its array of charms and charm bracelets as well as rings, necklaces and earrings, also offers free delivery as standard if you spend over £75.

It seems this year's limited edition charm is a poinsettia flower according to internet leaks. However, as it will probably only be available to the US and Canada, people in the UK might have to find a friend to buy it.

Did you know?

Black Friday 2015 saw us collectively spend £2bn in shops and online in the 24 hour period, and £3.3bn overall over the entire four day weekend.

By 9.10pm, Black Friday had already become Amazon’s biggest sales day ever in the UK, with more than six million items ordered.

Other retailers - such as John Lewis, Argos, Boots, Tesco and Game - all struggled to cope with the volume of online orders and saw significant downtime on their respective websites.